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simpler

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Ryan Oldenburg 2020-12-04 19:18:46 -06:00
parent b2a345ca40
commit a9ea7f2872
1 changed files with 6 additions and 11 deletions
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17
src/pixie/common.nim
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@ -16,19 +16,14 @@ proc intersects*(a, b: Segment, at: var Vec2): bool {.inline.} =
## Checks if the a segment intersects b segment. ## Checks if the a segment intersects b segment.
## If it returns true, at will have point of intersection ## If it returns true, at will have point of intersection
let let
s1x = a.to.x - a.at.x s1 = a.to - a.at
s1y = a.to.y - a.at.y s2 = b.to - b.at
s2x = b.to.x - b.at.x denominator = (-s2.x * s1.y + s1.x * s2.y)
s2y = b.to.y - b.at.y s = (-s1.y * (a.at.x - b.at.x) + s1.x * (a.at.y - b.at.y)) / denominator
t = (s2.x * (a.at.y - b.at.y) - s2.y * (a.at.x - b.at.x)) / denominator
let
denominator = (-s2x * s1y + s1x * s2y)
s = (-s1y * (a.at.x - b.at.x) + s1x * (a.at.y - b.at.y)) / denominator
t = (s2x * (a.at.y - b.at.y) - s2y * (a.at.x - b.at.x)) / denominator
if s >= 0 and s < 1 and t >= 0 and t < 1: if s >= 0 and s < 1 and t >= 0 and t < 1:
at.x = a.at.x + (t * s1x) at = a.at + (t * s1)
at.y = a.at.y + (t * s1y)
return true return true
return false return false